Detailed calculation of M40 concrete mix design | IS – 10262:2009 |IS -456:2000

In this emerging world of modern design of structures, Concrete acts as the backbone of civil engineering. A structural engineer’s first and foremost objective is to build an efficient and durable concrete structure that is also aesthetically pleasing. Here comes the role of a concrete designer. When the aim is to build a concrete structure that is efficient and durable, this demands to follow the concrete mix design steps as per IS codes (IS- 10262:2009 and IS- 456:2000).

If you are searching for detailed step by step procedure for concrete mix design of M40 grade using IS – 10262:2009 and IS – 456:2000….

Then yes you are in the write place!!!

Before reading this post just go and check “Concrete mix design procedure as per IS 10262:2009 & IS 456:2000” .

This post will help you to have a brief idea of different parameters required and will also make you aware about the different experimental data required for conducting the mix design of concrete.

Concrete Mix Design

  • Calculate cement, sand and aggregate quantity in concrete. 
  • Calculate the number of premix bags required for your project.
  • Option to set your own size and rate of premix bags.
  • Calculate the volume of concrete required for slabs, walls, footings and columns.
  • Calculate the weight of ingredients required for preparing the calculated volume of concrete.
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Detailed calculation for M40 Grade mix

The different design stipulations required for the desired mix are shown in the table below:

Stipulations for proportioning
Type of ConcreteRCC
Grade DesignationM40
Shape of ParticleAngular
Slump110 mm
Water- Cement Ratio0.50
Exposure ConditionSevere
Concrete PlacementPump
Degree of SupervisionGood

The different experiemental data required for the desiered mix are shown in the table below:

Sieve analysis
Fine AggregateZone 2
Coarse Aggregate20 mm
Chemical Admixture
Volume ( By mass of cement)2%
Water Content ReductionZero
Test data for materials
Standard Deviation5 MPa
Specific Gravity of Fine Aggregate2.74
Specific Gravity of Coarse Aggregate2.74
Specific Gravity of Cement3.15
Specific Gravity of Admixture1.00
Water absorption of Fine Aggregate1.0 %
Water absorption of Coarse Aggregate0.5%
Free Surface Moisture of Fine AggregateZero
Free Surface Moisture of Coarse AggregateZero

Step by step detailed procedure for concrete mix design of M40 grade as per IS – 10262:2009 and IS- 456:2000

Step 1: Calculate the target mean compressive strength at 28 days

target mean compressive strengthcharacteristic strength + 1.65 X Standard Deviation
target mean compressive strength40 + 1.65 X 5 = 48.25 N/mm2

Where sufficient test results for a particular grade of concrete are not available, the value of standard deviation could be taken from Table 1 of IS10262.

Step 2: Selection of maximum water/cement ratio

The maximum water-cement ratio should be selected as per Table 5 of IS – 456: 2000.

Maximum water-cement ratio 0.45
​ Adopted water-cement ratio0.45

Step 3: Estimation of entrapped air

For the maximum size of aggregate used the air content is estimated.

Step 4: Selection of water content and fine to total aggregate ratio

The selection of water content is based on Table 2 of IS:10262:2009.

Maximum water content for 20 mm aggregate and a slump value of 25 to 50 mm = 186.00 l.

But in our problem the value of slump is 110 mm, so we need to alter the water content.

Estimated water content186 + 7/100 X 186 = 199.39 litres

Step 5: Calculation of Cement content

The cement content per unit volume of concrete is computed sing Table 5 of IS:456:2000:

Minimum cement content for mild expossure condition320 kg/ m3
Maximum cement content450 kg/ m3
cement content 199.39/0.45 = 443.09 kg / m3

Check : 320 kg/ m3 < 443.09 kg / m3 < 450 kg/ m3 Hence O.K.

Step 6: Calculation of aggregate content

Volume of coarse aggregate per unit volume of total aggregate for corresponding to 20 mm maximum size and zone I of fine aggregate = 0.62 – Table 3 of IS- 10262:2009.

Correction:

Based on water cement ratio0.01
Based on placement10.00

Hence Volume

Coarse aggregate0.57
Fine aggregate0.43

$$
V=\left[W+\left(C / S_{c}\right)+(1 / P) \cdot\left(f_{a} / S_{f a}\right)\right] \times(1 / 1000)
$$

$$
C_{a}=1- P / P \times f_{a} \times S_{ca}/ S_{fa}
$$

Mass of Coarse aggregate1025.27 kg / m3
Mass of Fine aggregate782.97 kg / m3

Step 7: Computation of actual quantities required for a concrete mix – Trial mix

Water Correction

Extra quantity of water to be added

Coarse aggregate5.13 kg
Fine aggregate7.83 kg

Mix Design
Cement443 kg / m3
Water212 kg / m3
Fine Aggregate775 kg / m3
Coarse Aggregate1020 kg / m3

1 : 2.03 : 2.66

Cement : Coarse Aggregate : Fine Aggregate

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In order to check the efficiency of the designed concrete mix we shall prepare different trial mixes and the same are tested to check the strength and workability of designed concrete mix. If the designed concrete mix fails to meet the desired properties then minor adjustment is done in the water cement ratio and aggregate quantities, then again the trial mixes are prepared.

Hope this post helped you to learn the step by step procedure for concrete mix design using IS code ( IS – 10262: 2009 and IS – 456: 2000)

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